What is the answer to log_{2}(x^2-3x+4)=3 ?

The answer to log_{2}(x^2-3x+4)=3 is x=4,x=-1

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log_{2}(x^2-3x+4)=3

lo g_{2} (x^{2} - 3 x + 4) = 3

x = 4, x = - 1

Solution steps

lo g_{2} (x^{2} - 3 x + 4) = 3

Apply log rules

x^{2} - 3 x + 4 = 8

Solve

x^{2} - 3 x + 4 = 8 : x = 4, x = - 1

x = 4, x = - 1

2 ln (x) - ln (7) = ln (112)

lo g_{3} (x^{2} - 8) = 0

4 x^{3} ln (x) + x^{3} = 0

2 ln (x) = 6

2 ln (x) = 0

What is the answer to log_{2}(x^2-3x+4)=3 ?
The answer to log_{2}(x^2-3x+4)=3 is x=4,x=-1
Solve for x: log_{2}(x^2-3x+4)=3
The solution is x=4,x=-1