What is the answer to log_{2}(x+2)=-1 ?

The answer to log_{2}(x+2)=-1 is x=-3/2

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log_{2}(x+2)=-1

lo g_{2} (x + 2) = - 1

x = - \frac{3}{2}

Decimal

x = - 1.5

Solution steps

lo g_{2} (x + 2) = - 1

Apply log rules

x + 2 = \frac{1}{2}

Solve

x + 2 = \frac{1}{2} : x = - \frac{3}{2}

x = - \frac{3}{2}

lo g_{3} (x^{2} - 5 x - 9) = 3

lo g_{5} (4 x + 5) = 2

ln (9 x - 4) = 4

lo g_{7} (4 x - 11) = 2

lo g_{a} (5) = 0.02