What is the answer to log_{2}(x^2-4x-1)=2 ?

The answer to log_{2}(x^2-4x-1)=2 is x=5,x=-1

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log_{2}(x^2-4x-1)=2

lo g_{2} (x^{2} - 4 x - 1) = 2

x = 5, x = - 1

Solution steps

lo g_{2} (x^{2} - 4 x - 1) = 2

Apply log rules

x^{2} - 4 x - 1 = 4

Solve

x^{2} - 4 x - 1 = 4 : x = 5, x = - 1

x = 5, x = - 1

lo g_{16} (x) = \frac{5}{2}

ln (2) + ln (k - 4) = \frac{1}{3}

x^{4 + l o g_{3} (x)} = \frac{x}{9}

lo g_{5} (x^{2} + x + 4) = - 3

lo g_{\frac{1}{7}} (x) = - 3

What is the answer to log_{2}(x^2-4x-1)=2 ?
The answer to log_{2}(x^2-4x-1)=2 is x=5,x=-1
Solve for x: log_{2}(x^2-4x-1)=2
The solution is x=5,x=-1