What is the answer to 2log_{10}(x)-log_{10}(x+6)=0 ?

The answer to 2log_{10}(x)-log_{10}(x+6)=0 is x=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2log_{10}(x)-log_{10}(x+6)=0

2 lo g_{10} (x) - lo g_{10} (x + 6) = 0

x = 3

Solution steps

2 lo g_{10} (x) - lo g_{10} (x + 6) = 0

Apply log rules

x^{2} = x + 6

Solve

x^{2} = x + 6 : x = 3, x = - 2

x = 3, x = - 2

Verify Solutions:

x = 3

True

, x = - 2

False

The solution is

x = 3

10 lo g_{5} (9 x - 5) = 35

2 lo g_{10} (x) = 3 + lo g_{10} (\frac{x}{10})

60 = 10 lo g_{10} (x)

lo g_{10} (x + 1) = 2

ln (x) + ln (x - 7) = ln (6 x)

What is the answer to 2log_{10}(x)-log_{10}(x+6)=0 ?
The answer to 2log_{10}(x)-log_{10}(x+6)=0 is x=3
Solve for x: 2log_{10}(x)-log_{10}(x+6)=0
The solution is x=3