What are the solutions to the equation m^2-12=109 ?

The solutions to the equation m^2-12=109 are m=11,m=-11

Find the zeros of m^2-12=109

The zeros of m^2-12=109 are m=11,m=-11

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m^{2} - 12 = 109

m = 11, m = - 11

Solution steps

m^{2} - 12 = 109

Move

12

to the right side

m^{2} = 121

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = 121, m = - 121

121 = 11

- 121 = - 11

m = 11, m = - 11

6 x^{2} - 5 < x

x - 5 \geq 0

\frac{x}{3} = \frac{x}{2} - 2

\frac{4 + 5 i}{3 - 2 i}

\frac{x}{8} = \frac{7}{4}

What are the solutions to the equation m^2-12=109 ?
The solutions to the equation m^2-12=109 are m=11,m=-11
Find the zeros of m^2-12=109
The zeros of m^2-12=109 are m=11,m=-11