What is the answer to ln(2x-3)+1=0 ?

The answer to ln(2x-3)+1=0 is x=(1+3e)/(2e)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

ln(2x-3)+1=0

ln (2 x - 3) + 1 = 0

x = \frac{1 + 3 e}{2 e}

Decimal

x = 1.68393 \dots

Solution steps

ln (2 x - 3) + 1 = 0

Move

1

to the right side

ln (2 x - 3) = - 1

Apply log rules

2 x - 3 = \frac{1}{e}

Solve

2 x - 3 = \frac{1}{e} : x = \frac{1 + 3 e}{2 e}

x = \frac{1 + 3 e}{2 e}

Verify Solutions:

x = \frac{1 + 3 e}{2 e}

True

The solution is

x = \frac{1 + 3 e}{2 e}

lo g_{3} (\frac{3}{x}) = - 3

lo g_{4} (3 x - 2) = 3

lo g_{x} (20) = 2

2 ln (x) = ln (4 x + 5)

2 lo g_{10} (x) = lo g_{10} (2) + lo g_{10} (3 x - 4)

What is the answer to ln(2x-3)+1=0 ?
The answer to ln(2x-3)+1=0 is x=(1+3e)/(2e)
Solve for x: ln(2x-3)+1=0
The solution is x=(1+3e)/(2e)