What is the answer to log_{10}((x-2)^2)=12 ?

The answer to log_{10}((x-2)^2)=12 is x=1000002,x=-999998

Solve for x: log_{10}((x-2)^2)=12

The solution is x=1000002,x=-999998

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

lo g_{10} ((x - 2)^{2}) = 12

x = 1000002, x = - 999998

Solution steps

lo g_{10} ((x - 2)^{2}) = 12

Apply log rules

(x - 2)^{2} = 1 0^{12}

Solve

(x - 2)^{2} = 1 0^{12} : x = 1000002, x = - 999998

x = 1000002, x = - 999998

lo g_{3} (x + 1) = e

lo g_{10} (x) + lo g_{10} (5) = 2

10 = 10.07 + lo g_{10} (x)

4 + 3 lo g_{10} (2 x) = 16

2 - ln (x) = 0

What is the answer to log_{10}((x-2)^2)=12 ?
The answer to log_{10}((x-2)^2)=12 is x=1000002,x=-999998
Solve for x: log_{10}((x-2)^2)=12
The solution is x=1000002,x=-999998