What is the answer to solvefor x,ln(y)=ln(x)+c ?

The answer to solvefor x,ln(y)=ln(x)+c is x=e^{-c}y

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solvefor x,ln(y)=ln(x)+c

solve for

x, ln (y) = ln (x) + c

x = e^{- c} y

Solution steps

ln (y) = ln (x) + c

Switch sides

ln (x) + c = ln (y)

Move

c

to the right side

ln (x) = ln (y) - c

Apply log rules

x = e^{- c} y

lo g_{4} (x^{2} + 5 x + 6) = 1

25 = 5 x + 3 ln (x - 4)

lo g_{x + 1} (9) = 2

lo g_{3} (4 x - 7) = 2

lo g_{10} (2 - 5 x) = 1

What is the answer to solvefor x,ln(y)=ln(x)+c ?
The answer to solvefor x,ln(y)=ln(x)+c is x=e^{-c}y