What is the answer to ln((x-1)^2)=2 ?

The answer to ln((x-1)^2)=2 is x=e+1,x=-e+1

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ln((x-1)^2)=2

ln ((x - 1)^{2}) = 2

x = e + 1, x = - e + 1

Decimal

x = 3.71828 \dots, x = - 1.71828 \dots

Solution steps

ln ((x - 1)^{2}) = 2

Apply log rules

(x - 1)^{2} = e^{2}

Solve

(x - 1)^{2} = e^{2} : x = e + 1, x = - e + 1

x = e + 1, x = - e + 1

lo g_{x} (100) = - 3

ln (13 x) + 1 = 0

lo g_{10} (2 x) + lo g_{10} (3) = lo g_{10} (30)

lo g_{10} (x) = 10

lo g_{3} (1 + x) = 2

What is the answer to ln((x-1)^2)=2 ?
The answer to ln((x-1)^2)=2 is x=e+1,x=-e+1
Solve for x: ln((x-1)^2)=2
The solution is x=e+1,x=-e+1