What is the answer to log_{-2x+2}(2x^2-10x+4)=2 ?

The answer to log_{-2x+2}(2x^2-10x+4)=2 is x=-1,x=0

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log_{-2x+2}(2x^2-10x+4)=2

lo g_{- 2 x + 2} (2 x^{2} - 10 x + 4) = 2

x = - 1, x = 0

Solution steps

lo g_{- 2 x + 2} (2 x^{2} - 10 x + 4) = 2

Apply log rules

\frac{ln ( 2 x ^{2} - 10 x + 4 )}{ln ( - 2 x + 2 )} = 2

Multiply both sides by

ln (- 2 x + 2)

\frac{ln ( 2 x ^{2} - 10 x + 4 )}{ln ( - 2 x + 2 )} ln (- 2 x + 2) = 2 ln (- 2 x + 2)

Simplify

ln (2 x^{2} - 10 x + 4) = 2 ln (- 2 x + 2)

Apply log rules

2 x^{2} - 10 x + 4 = (- 2 x + 2)^{2}

Solve

2 x^{2} - 10 x + 4 = (- 2 x + 2)^{2} : x = - 1, x = 0

x = - 1, x = 0

Verify Solutions:

x = - 1

True

, x = 0

True

The solutions are

x = - 1, x = 0

lo g_{10} (x + 5) = lo g_{10} (x) + lo g_{10} (5)

6 x ln (x) + 5 x = 0

lo g_{8} (p^{2} + 15) = 2

y, lo g_{y} (x) = - 11

lo g_{x} (2 x + 24) = 2

What is the answer to log_{-2x+2}(2x^2-10x+4)=2 ?
The answer to log_{-2x+2}(2x^2-10x+4)=2 is x=-1,x=0
Solve for x: log_{-2x+2}(2x^2-10x+4)=2
The solution is x=-1,x=0