What are the solutions to the equation z^2=1 ?

The solutions to the equation z^2=1 are z=1,z=-1

Find the zeros of z^2=1

The zeros of z^2=1 are z=1,z=-1

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z^{2} = 1

z = 1, z = - 1

Solution steps

z^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

z = 1, z = - 1

1 = 1

- 1 = - 1

z = 1, z = - 1

\frac{2}{- \frac{1}{3}}

(3 x - 1)^{2} = 1

6 (5 k - 8) - 20 = 11 (2 k - 3) + 3 k

lo g_{5} (3125)

y - 12 = 11

What are the solutions to the equation z^2=1 ?
The solutions to the equation z^2=1 are z=1,z=-1
Find the zeros of z^2=1
The zeros of z^2=1 are z=1,z=-1