What is the answer to log_{10}(3x+9)= 1/3 ?

The answer to log_{10}(3x+9)= 1/3 is x=(\sqrt[3]{10}-9)/3

Solve for x: log_{10}(3x+9)= 1/3

The solution is x=(\sqrt[3]{10}-9)/3

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lo g_{10} (3 x + 9) = \frac{1}{3}

x = \frac{3 10 - 9}{3}

Decimal

x = - 2.28185 \dots

Solution steps

lo g_{10} (3 x + 9) = \frac{1}{3}

Apply log rules

3 x + 9 = 310

Solve

3 x + 9 = 310 : x = \frac{3 10 - 9}{3}

x = \frac{3 10 - 9}{3}

lo g_{x} (5) = - 4

lo g_{3} (7 - x) = 2 lo g_{3} (7)

ln (x - 3) - ln (x - 2) = 5

lo g_{x + 4} (3 x^{2} - 2 x + 16) = 2

lo g_{5} (x + 6) = 2

What is the answer to log_{10}(3x+9)= 1/3 ?
The answer to log_{10}(3x+9)= 1/3 is x=(\sqrt[3]{10}-9)/3
Solve for x: log_{10}(3x+9)= 1/3
The solution is x=(\sqrt[3]{10}-9)/3