What is the answer to log_{10}(x+4)=log_{10}(x)+log_{10}(4) ?

The answer to log_{10}(x+4)=log_{10}(x)+log_{10}(4) is x= 4/3

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log_{10}(x+4)=log_{10}(x)+log_{10}(4)

lo g_{10} (x + 4) = lo g_{10} (x) + lo g_{10} (4)

x = \frac{4}{3}

Decimal

x = 1.33333 \dots

Solution steps

lo g_{10} (x + 4) = lo g_{10} (x) + lo g_{10} (4)

Apply log rules

x + 4 = x \cdot 4

Solve

x + 4 = x \cdot 4 : x = \frac{4}{3}

x = \frac{4}{3}

Verify Solutions:

x = \frac{4}{3}

True

The solution is

x = \frac{4}{3}

ln^{2} (x) + ln (x^{3}) + 2 = 0

lo g_{3} (x) = - \frac{1}{4}

x + lo g_{2} (3 - 2^{x}) = 1

lo g_{9} (a) = 2

2 = lo g_{3} (t)

What is the answer to log_{10}(x+4)=log_{10}(x)+log_{10}(4) ?
The answer to log_{10}(x+4)=log_{10}(x)+log_{10}(4) is x= 4/3
Solve for x: log_{10}(x+4)=log_{10}(x)+log_{10}(4)
The solution is x= 4/3