What is the answer to 0=ln(x^2-16) ?

The answer to 0=ln(x^2-16) is x=sqrt(17),x=-sqrt(17)

Solve for x: 0=ln(x^2-16)

The solution is x=sqrt(17),x=-sqrt(17)

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0 = ln (x^{2} - 16)

x = 17, x = - 17

Decimal

x = 4.12310 \dots, x = - 4.12310 \dots

Solution steps

0 = ln (x^{2} - 16)

Apply log rules

1 = x^{2} - 16

Solve

1 = x^{2} - 16 : x = 17, x = - 17

x = 17, x = - 17

lo g_{16} (x) = - \frac{3}{4}

- \frac{1}{2} = ln (x)

lo g_{7} (x) = - 4

91.87 = 0.5826 ln (x) + 97.51

lo g_{x + 1} (x^{2} + 7) = 2

What is the answer to 0=ln(x^2-16) ?
The answer to 0=ln(x^2-16) is x=sqrt(17),x=-sqrt(17)
Solve for x: 0=ln(x^2-16)
The solution is x=sqrt(17),x=-sqrt(17)