What is the answer to log_{10}(x)+log_{10}(x+2)=2 ?

The answer to log_{10}(x)+log_{10}(x+2)=2 is x=-1+sqrt(101)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{10}(x)+log_{10}(x+2)=2

lo g_{10} (x) + lo g_{10} (x + 2) = 2

x = - 1 + 101

Decimal

x = 9.04987 \dots

Solution steps

lo g_{10} (x) + lo g_{10} (x + 2) = 2

Apply log rules

x (x + 2) = 100

Solve

x (x + 2) = 100 : x = - 1 + 101, x = - 1 - 101

x = - 1 + 101, x = - 1 - 101

Verify Solutions:

x = - 1 + 101

True

, x = - 1 - 101

False

The solution is

x = - 1 + 101

x, t (x) = lo g_{4} (x + 2)

ln (x) = \frac{3}{2}

ln (x^{2}) = 0

lo g_{a} (8) = 6

0 = - ln (- x)

What is the answer to log_{10}(x)+log_{10}(x+2)=2 ?
The answer to log_{10}(x)+log_{10}(x+2)=2 is x=-1+sqrt(101)
Solve for x: log_{10}(x)+log_{10}(x+2)=2
The solution is x=-1+sqrt(101)