What is the answer to 1+log_{3}(x+1)=0 ?

The answer to 1+log_{3}(x+1)=0 is x=-2/3

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1+log_{3}(x+1)=0

1 + lo g_{3} (x + 1) = 0

x = - \frac{2}{3}

Decimal

x = - 0.66666 \dots

Solution steps

1 + lo g_{3} (x + 1) = 0

Move

1

to the right side

lo g_{3} (x + 1) = - 1

Apply log rules

x + 1 = \frac{1}{3}

Solve

x + 1 = \frac{1}{3} : x = - \frac{2}{3}

x = - \frac{2}{3}

Verify Solutions:

x = - \frac{2}{3}

True

The solution is

x = - \frac{2}{3}

2 x \times ln (x) + x = 0

lo g_{9} (\frac{x - 6}{x + 3}) = 1

lo g_{x - 2} (9) = 2

lo g_{x} (125) = 9

lo g_{x} (125) = 6

What is the answer to 1+log_{3}(x+1)=0 ?
The answer to 1+log_{3}(x+1)=0 is x=-2/3
Solve for x: 1+log_{3}(x+1)=0
The solution is x=-2/3