What is the answer to 2log_{10}(3-x)=1 ?

The answer to 2log_{10}(3-x)=1 is x=-sqrt(10)+3

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2log_{10}(3-x)=1

2 lo g_{10} (3 - x) = 1

x = - 10 + 3

Decimal

x = - 0.16227 \dots

Solution steps

2 lo g_{10} (3 - x) = 1

Divide both sides by

2

lo g_{10} (3 - x) = \frac{1}{2}

Apply log rules

3 - x = 10

Solve

3 - x = 10 : x = - 10 + 3

x = - 10 + 3

Verify Solutions:

x = - 10 + 3

True

The solution is

x = - 10 + 3

lo g_{2} (x + 1) = 2

lo g_{2} (x^{3}) = 3

lo g_{7} (7 x) = 2

ln (x) + ln (x + 4) = 3

ln (x) + ln (x - 1) = 5

What is the answer to 2log_{10}(3-x)=1 ?
The answer to 2log_{10}(3-x)=1 is x=-sqrt(10)+3
Solve for x: 2log_{10}(3-x)=1
The solution is x=-sqrt(10)+3