What is factor 1+4x+4x^2 ?

The solution to factor 1+4x+4x^2 is (2x+1)^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor 1+4x+4x^2

factor

1 + 4 x + 4 x^{2}

(2 x + 1)^{2}

Solution steps

1 + 4 x + 4 x^{2}

Write in the standard form

= 4 x^{2} + 4 x + 1

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

4 x^{2} = (2 x)^{2}

1 = 1^{2}

4 x = 2 \cdot 2 x \cdot 1

= (2 x)^{2} + 2 \cdot 2 x \cdot 1 + 1^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

(2 x)^{2} + 2 \cdot 2 x \cdot 1 + 1^{2} = (2 x + 1)^{2}

= (2 x + 1)^{2}

5 x^{2} + 22 x + 21

x^{3} - 4 x < 0

12.5 (3 x - 1) + 132.4 = (2.8 - 4 x) \cdot 0.5

(- 4 - 4 i) (- 5 - 3 i)