What is the answer to 100=12\times log_{1.5}(t)+7 ?

The answer to 100=12\times log_{1.5}(t)+7 is t=1.5^{31/4}

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100=12\times log_{1.5}(t)+7

100 = 12 \cdot lo g_{1.5} (t) + 7

t = 1. 5^{\frac{31}{4}}

Decimal

t = 23.15833 \dots

Solution steps

100 = 12 lo g_{1.5} (t) + 7

Switch sides

12 lo g_{1.5} (t) + 7 = 100

Move

7

to the right side

12 lo g_{1.5} (t) = 93

Divide both sides by

12

lo g_{1.5} (t) = \frac{31}{4}

Apply log rules

t = 1. 5^{\frac{31}{4}}

Verify Solutions:

t = 1. 5^{\frac{31}{4}}

True

The solution is

t = 1. 5^{\frac{31}{4}}

lo g_{x - 2} (16) = 2

lo g_{x} (x^{2} - 2) = 1

lo g_{8} (5 x + 47) = 3

y, lo g_{8} (x y) = 3

2 x + 2 ln (x) - 2 = 0

What is the answer to 100=12\times log_{1.5}(t)+7 ?
The answer to 100=12\times log_{1.5}(t)+7 is t=1.5^{31/4}
Solve for t: 100=12\times log_{1.5}(t)+7
The solution is t=1.5^{31/4}