What is the answer to 2log_{2}(x-4)+log_{2}(2)=3 ?

The answer to 2log_{2}(x-4)+log_{2}(2)=3 is x=6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2log_{2}(x-4)+log_{2}(2)=3

2 lo g_{2} (x - 4) + lo g_{2} (2) = 3

x = 6

Solution steps

2 lo g_{2} (x - 4) + lo g_{2} (2) = 3

Move

lo g_{2} (2)

to the right side

2 lo g_{2} (x - 4) = 3 - lo g_{2} (2)

Divide both sides by

2

lo g_{2} (x - 4) = \frac{3 - lo g _{2} ( 2 )}{2}

Apply log rules

x - 4 = 2

Solve

x - 4 = 2 : x = 6

x = 6

Verify Solutions:

x = 6

True

The solution is

x = 6

lo g_{10} (x^{2}) = - 2

ln (1 - x) = \frac{10}{3} x - 4.16

lo g_{2} (x - 3) = 0

lo g_{x} (2 x^{2} - 9 x + 14) = 2

lo g_{10} (5 - 2 x) = 1

What is the answer to 2log_{2}(x-4)+log_{2}(2)=3 ?
The answer to 2log_{2}(x-4)+log_{2}(2)=3 is x=6
Solve for x: 2log_{2}(x-4)+log_{2}(2)=3
The solution is x=6