What are the solutions to the equation -2x^2-x-1=0 ?

The solutions to the equation -2x^2-x-1=0 are x=-1/4-i(sqrt(7))/4 ,x=-1/4+i(sqrt(7))/4

Find the zeros of -2x^2-x-1=0

The zeros of -2x^2-x-1=0 are x=-1/4-i(sqrt(7))/4 ,x=-1/4+i(sqrt(7))/4

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- 2 x^{2} - x - 1 = 0

x = - \frac{1}{4} - i \frac{7}{4}, x = - \frac{1}{4} + i \frac{7}{4}

Solution steps

- 2 x^{2} - x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 2 ) ( - 1 )}{2 ( - 2 )}

Simplify

(- 1)^{2} - 4 (- 2) (- 1) : 7 i

x_{1, 2} = \frac{- ( - 1 ) \pm 7 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 7 i}{2 ( - 2 )}, x_{2} = \frac{- ( - 1 ) - 7 i}{2 ( - 2 )}

x = \frac{- ( - 1 ) + 7 i}{2 ( - 2 )} : - \frac{1}{4} - i \frac{7}{4}

x = \frac{- ( - 1 ) - 7 i}{2 ( - 2 )} : - \frac{1}{4} + i \frac{7}{4}

The solutions to the quadratic equation are:

x = - \frac{1}{4} - i \frac{7}{4}, x = - \frac{1}{4} + i \frac{7}{4}

3 m^{2} + 8 m + 5

\frac{3}{8 ( 4 ) ^{\frac{1}{2}}}

30 m n^{5} + 6 m n^{2} + 18 mn

\frac{2 π}{3} + \frac{π}{6}

7^{2} + 5^{2} = c^{2}

What are the solutions to the equation -2x^2-x-1=0 ?
The solutions to the equation -2x^2-x-1=0 are x=-1/4-i(sqrt(7))/4 ,x=-1/4+i(sqrt(7))/4
Find the zeros of -2x^2-x-1=0
The zeros of -2x^2-x-1=0 are x=-1/4-i(sqrt(7))/4 ,x=-1/4+i(sqrt(7))/4