What is the answer to ln(2x-7)+ln(4)=3 ?

The answer to ln(2x-7)+ln(4)=3 is x=(e^3+28)/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

ln(2x-7)+ln(4)=3

ln (2 x - 7) + ln (4) = 3

x = \frac{e ^{3} + 28}{8}

Decimal

x = 6.01069 \dots

Solution steps

ln (2 x - 7) + ln (4) = 3

Move

ln (4)

to the right side

ln (2 x - 7) = 3 - ln (4)

Apply log rules

2 x - 7 = \frac{e ^{3}}{4}

Solve

2 x - 7 = \frac{e ^{3}}{4} : x = \frac{e ^{3} + 28}{8}

x = \frac{e ^{3} + 28}{8}

Verify Solutions:

x = \frac{e ^{3} + 28}{8}

True

The solution is

x = \frac{e ^{3} + 28}{8}

lo g_{a} (16) = 2

5 x^{4} ln (x) + x^{4}

ln (x) + ln (x + 10) = 4

3 lo g_{10} (x) = lo g_{10} (125)

\frac{1 + ln ( x )}{2} = 0

What is the answer to ln(2x-7)+ln(4)=3 ?
The answer to ln(2x-7)+ln(4)=3 is x=(e^3+28)/8
Solve for x: ln(2x-7)+ln(4)=3
The solution is x=(e^3+28)/8