What is the answer to log_{1/7}(7-3x)=-2 ?

The answer to log_{1/7}(7-3x)=-2 is x=-14

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log_{1/7}(7-3x)=-2

lo g_{\frac{1}{7}} (7 - 3 x) = - 2

x = - 14

Solution steps

lo g_{\frac{1}{7}} (7 - 3 x) = - 2

Apply log rules

7 - 3 x = 49

Solve

7 - 3 x = 49 : x = - 14

x = - 14

lo g_{2} (3 x + 6) = 1

lo g_{10} (x) + lo g_{10} (x + 4) = 6

lo g_{x - 1} (25) = 2

lo g_{x} (225) = 2

- 0.03 = 20 lo g_{10} (x)

What is the answer to log_{1/7}(7-3x)=-2 ?
The answer to log_{1/7}(7-3x)=-2 is x=-14
Solve for x: log_{1/7}(7-3x)=-2
The solution is x=-14