What is the answer to log_{2}(x-1)= 1/6 ?

The answer to log_{2}(x-1)= 1/6 is x=\sqrt[6]{2}+1

Solve for x: log_{2}(x-1)= 1/6

The solution is x=\sqrt[6]{2}+1

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lo g_{2} (x - 1) = \frac{1}{6}

x = 62 + 1

Decimal

x = 2.12246 \dots

Solution steps

lo g_{2} (x - 1) = \frac{1}{6}

Apply log rules

x - 1 = 62

Solve

x - 1 = 62 : x = 62 + 1

x = 62 + 1

lo g_{10} (x) + lo g_{10} (x + 15) = 2

lo g_{e} (2 x - 1) = - 3

lo g_{4} (x) = x + 2

lo g_{5} (5 - x) = 2 lo g_{5} (3)

lo g_{10} (- m) + 2 = 4

What is the answer to log_{2}(x-1)= 1/6 ?
The answer to log_{2}(x-1)= 1/6 is x=\sqrt[6]{2}+1
Solve for x: log_{2}(x-1)= 1/6
The solution is x=\sqrt[6]{2}+1