What is the answer to log_{10}(x)-log_{10}(x+2)=1 ?

The answer to log_{10}(x)-log_{10}(x+2)=1 is No Solution for x\in\mathbb{R}

Solve for x: log_{10}(x)-log_{10}(x+2)=1

The solution is No Solution for x\in\mathbb{R}

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lo g_{10} (x) - lo g_{10} (x + 2) = 1

No Solution for x \in R

Solution steps

lo g_{10} (x) - lo g_{10} (x + 2) = 1

Add

lo g_{10} (x + 2)

to both sides

lo g_{10} (x) - lo g_{10} (x + 2) + lo g_{10} (x + 2) = 1 + lo g_{10} (x + 2)

Simplify

lo g_{10} (x) = 1 + lo g_{10} (x + 2)

Apply log rules

x = 10 (x + 2)

Solve

x = 10 (x + 2) : x = - \frac{20}{9}

x = - \frac{20}{9}

Verify Solutions:

x = - \frac{20}{9}

False

The solution is

No Solution for x \in R

lo g_{10} (x + 6) = lo g_{10} (x) + lo g_{10} (6)

5 x + 3 ln (x - 4) = 25

lo g_{2} (\frac{x}{4}) = 1

lo g_{5} (9 - 2 x) = 2

lo g_{10} (2 x - 3) = lo g_{10} (x - 4) + 1

What is the answer to log_{10}(x)-log_{10}(x+2)=1 ?
The answer to log_{10}(x)-log_{10}(x+2)=1 is No Solution for x\in\mathbb{R}
Solve for x: log_{10}(x)-log_{10}(x+2)=1
The solution is No Solution for x\in\mathbb{R}