What is the answer to log_{1/6}(3-10x)=-2 ?

The answer to log_{1/6}(3-10x)=-2 is x=-33/10

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log_{1/6}(3-10x)=-2

lo g_{\frac{1}{6}} (3 - 10 x) = - 2

x = - \frac{33}{10}

Decimal

x = - 3.3

Solution steps

lo g_{\frac{1}{6}} (3 - 10 x) = - 2

Apply log rules

3 - 10 x = 36

Solve

3 - 10 x = 36 : x = - \frac{33}{10}

x = - \frac{33}{10}

lo g_{10} (3 x + 1) - lo g_{10} (2 x - 3) = 1 - lo g_{10} (5)

5 x^{4} ln (x) + x^{4} = 0

\frac{ln ( 6 b )}{6} = 0

2 lo g_{3} (x) = 2 lo g_{3} (4) - 4 lo g_{3} (5)

lo g_{12} (2 x - 6) + 3 = 3

What is the answer to log_{1/6}(3-10x)=-2 ?
The answer to log_{1/6}(3-10x)=-2 is x=-33/10
Solve for x: log_{1/6}(3-10x)=-2
The solution is x=-33/10