What is the answer to log_{x}(sqrt(2))=4 ?

The answer to log_{x}(sqrt(2))=4 is x=e^{(ln(2))/8}

Solve for x: log_{x}(sqrt(2))=4

The solution is x=e^{(ln(2))/8}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

lo g_{x} (2) = 4

x = e^{\frac{l n ( 2 )}{8}}

Decimal

x = 1.09050 \dots

Solution steps

lo g_{x} (2) = 4

Apply log rules

\frac{ln ( 2 )}{ln ( x )} = 4

Multiply both sides by

ln (x)

\frac{ln ( 2 )}{ln ( x )} ln (x) = 4 ln (x)

Apply log rules

x = e^{\frac{l n ( 2 )}{8}}

Verify Solutions:

x = e^{\frac{l n ( 2 )}{8}}

True

The solution is

x = e^{\frac{l n ( 2 )}{8}}

lo g_{2} (x + 5) = - 1

lo g_{3} (3 x - 3) = 2

- 1 = lo g_{3} (x)

\frac{e}{e - 1} = ln (x) + 1

x, z = ln (x - y)

What is the answer to log_{x}(sqrt(2))=4 ?
The answer to log_{x}(sqrt(2))=4 is x=e^{(ln(2))/8}
Solve for x: log_{x}(sqrt(2))=4
The solution is x=e^{(ln(2))/8}