What is the answer to log_{10}(x)+log_{10}(x+5)=1 ?

The answer to log_{10}(x)+log_{10}(x+5)=1 is x=(-5+sqrt(65))/2

Solve for x: log_{10}(x)+log_{10}(x+5)=1

The solution is x=(-5+sqrt(65))/2

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lo g_{10} (x) + lo g_{10} (x + 5) = 1

x = \frac{- 5 + 65}{2}

Decimal

x = 1.53112 \dots

Solution steps

lo g_{10} (x) + lo g_{10} (x + 5) = 1

Apply log rules

x (x + 5) = 10

Solve

x (x + 5) = 10 : x = \frac{- 5 + 65}{2}, x = \frac{- 5 - 65}{2}

x = \frac{- 5 + 65}{2}, x = \frac{- 5 - 65}{2}

Verify Solutions:

x = \frac{- 5 + 65}{2}

True

, x = \frac{- 5 - 65}{2}

False

The solution is

x = \frac{- 5 + 65}{2}

lo g_{10} (x) + lo g_{10} (x + 5) = 6

lo g_{3} (x) = 8

y, - y = lo g_{10} (x)

lo g_{10} (x) = 2

lo g_{4} (17 x - 4) = 3

What is the answer to log_{10}(x)+log_{10}(x+5)=1 ?
The answer to log_{10}(x)+log_{10}(x+5)=1 is x=(-5+sqrt(65))/2
Solve for x: log_{10}(x)+log_{10}(x+5)=1
The solution is x=(-5+sqrt(65))/2