What is the answer to r=sqrt((-3)^2+(\sqrt{3))^2} ?

The answer to r=sqrt((-3)^2+(\sqrt{3))^2} is r=2sqrt(3)

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r=sqrt((-3)^2+(\sqrt{3))^2}

r = (- 3)^{2} + (3)^{2}

r = 23

Decimal Notation

r = 3.46410 \dots

Solution steps

r = (- 3)^{2} + (3)^{2}

Simplify

(- 3)^{2} + (3)^{2} : 23

r = 23

10 \leq 1.02 - r

- \frac{4}{5} + \frac{4}{3}

x - 6 = - 8

\frac{6 !}{( 6 - 5 ) ! 5 !}

What is the answer to r=sqrt((-3)^2+(\sqrt{3))^2} ?
The answer to r=sqrt((-3)^2+(\sqrt{3))^2} is r=2sqrt(3)
Solve for r: r=sqrt((-3)^2+(\sqrt{3))^2}
The solution is r=2sqrt(3)