What is the answer to log_{1+x}(400/13)=20 ?

The answer to log_{1+x}(400/13)=20 is x=e^{(ln(400/13))/(20)}-1

Solve for x: log_{1+x}(400/13)=20

The solution is x=e^{(ln(400/13))/(20)}-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

lo g_{1 + x} (\frac{400}{13}) = 20

x = e^{\frac{l n ( \frac{400}{13} )}{20}} - 1

Decimal

x = 0.18687 \dots

Solution steps

lo g_{1 + x} (\frac{400}{13}) = 20

Apply log rules

\frac{ln ( \frac{400}{13} )}{ln ( 1 + x )} = 20

Multiply both sides by

ln (1 + x)

\frac{ln ( \frac{400}{13} )}{ln ( 1 + x )} ln (1 + x) = 20 ln (1 + x)

Simplify

ln (\frac{400}{13}) = 20 ln (1 + x)

Switch sides

20 ln (1 + x) = ln (\frac{400}{13})

Divide both sides by

20

ln (1 + x) = \frac{ln ( \frac{400}{13} )}{20}

Apply log rules

1 + x = e^{\frac{l n ( \frac{400}{13} )}{20}}

Solve

1 + x = e^{\frac{l n ( \frac{400}{13} )}{20}} : x = e^{\frac{l n ( \frac{400}{13} )}{20}} - 1

x = e^{\frac{l n ( \frac{400}{13} )}{20}} - 1

Verify Solutions:

x = e^{\frac{l n ( \frac{400}{13} )}{20}} - 1

True

The solution is

x = e^{\frac{l n ( \frac{400}{13} )}{20}} - 1

2 \times lo g_{3} (x) - 23 = 17

2 lo g_{5} (x - 2) = 6

2 (4 x ln (x) + 2 x) = 0

lo g_{10} (8) + lo g_{10} (x) = 1

lo g_{2 x} (x^{2} - 3 x + 14) = 3

What is the answer to log_{1+x}(400/13)=20 ?
The answer to log_{1+x}(400/13)=20 is x=e^{(ln(400/13))/(20)}-1
Solve for x: log_{1+x}(400/13)=20
The solution is x=e^{(ln(400/13))/(20)}-1