What is the answer to x(2ln(x)+1)=0 ?

The answer to x(2ln(x)+1)=0 is x= 1/(sqrt(e))

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x(2ln(x)+1)=0

x (2 ln (x) + 1) = 0

x = \frac{1}{e}

Decimal

x = 0.60653 \dots

Solution steps

x (2 ln (x) + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 ln (x) + 1 = 0

Solve

2 ln (x) + 1 = 0 : x = \frac{1}{e}

Verify Solutions:

x = 0

False

, x = \frac{1}{e}

True

The solution is

x = \frac{1}{e}

lo g_{2} (x) - 3 lo g_{10} (x) = 2

lo g_{5} (x) = 0

lo g_{5} (1 - 4 x) = 2

lo g_{3} (8 - 5 x) = 2

lo g_{x} (7) = - \frac{1}{2}

What is the answer to x(2ln(x)+1)=0 ?
The answer to x(2ln(x)+1)=0 is x= 1/(sqrt(e))
Solve for x: x(2ln(x)+1)=0
The solution is x= 1/(sqrt(e))