What is the answer to 26=10log_{10}(I/(10^{-16)}) ?

The answer to 26=10log_{10}(I/(10^{-16)}) is I= 1/(10^{13)*10^{2/5}}

Solve for I: 26=10log_{10}(I/(10^{-16)})

The solution is I= 1/(10^{13)*10^{2/5}}

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26 = 10 lo g_{10} (\frac{I}{1 0 ^{- 16}})

I = \frac{1}{1 0 ^{13} \cdot 1 0 ^{\frac{2}{5}}}

Decimal

I = 3.98107 E - 14

Solution steps

26 = 10 lo g_{10} (\frac{I}{1 0 ^{- 16}})

Switch sides

10 lo g_{10} (\frac{I}{1 0 ^{- 16}}) = 26

Divide both sides by

10

lo g_{10} (\frac{I}{1 0 ^{- 16}}) = \frac{13}{5}

Apply log rules

\frac{I}{1 0 ^{- 16}} = 1 0^{\frac{13}{5}}

Multiply both sides by

1 0^{- 16}

\frac{I}{1 0 ^{- 16}} \cdot 1 0^{- 16} = 1 0^{\frac{13}{5}} \cdot 1 0^{- 16}

Simplify

\frac{I}{1 0 ^{- 16}} \cdot 1 0^{- 16} : I

Simplify

1 0^{\frac{13}{5}} \cdot 1 0^{- 16} : 1 0^{\frac{3}{5} - 14}

I = 1 0^{\frac{3}{5} - 14}

Solve

I = 1 0^{\frac{3}{5} - 14} : I = \frac{1}{1 0 ^{13} \cdot 1 0 ^{\frac{2}{5}}}

I = \frac{1}{1 0 ^{13} \cdot 1 0 ^{\frac{2}{5}}}

Verify Solutions:

I = \frac{1}{1 0 ^{13} \cdot 1 0 ^{\frac{2}{5}}}

True

The solution is

I = \frac{1}{1 0 ^{13} \cdot 1 0 ^{\frac{2}{5}}}

lo g_{10} (x + 9) = lo g_{10} (x) + lo g_{10} (9)

lo g_{10} (2 x - 1) = 10

ln (3 x + 5) = 8

lo g_{x} (0.125) = 3

lo g_{10} (3 x - 4) = 2

What is the answer to 26=10log_{10}(I/(10^{-16)}) ?
The answer to 26=10log_{10}(I/(10^{-16)}) is I= 1/(10^{13)*10^{2/5}}
Solve for I: 26=10log_{10}(I/(10^{-16)})
The solution is I= 1/(10^{13)*10^{2/5}}