What is the answer to log_{10}(x)(32)=-5 ?

The answer to log_{10}(x)(32)=-5 is x= 1/(10^{5/32)}

Solve for x: log_{10}(x)(32)=-5

The solution is x= 1/(10^{5/32)}

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lo g_{10} (x) (32) = - 5

x = \frac{1}{1 0 ^{\frac{5}{32}}}

Decimal

x = 0.69783 \dots

Solution steps

lo g_{10} (x) (32) = - 5

Divide both sides by

32

lo g_{10} (x) = - \frac{5}{32}

Apply log rules

x = \frac{1}{1 0 ^{\frac{5}{32}}}

Verify Solutions:

x = \frac{1}{1 0 ^{\frac{5}{32}}}

True

The solution is

x = \frac{1}{1 0 ^{\frac{5}{32}}}

lo g_{x} (2) = - 4

lo g_{22} (x - 5) = 0

ln (x + 2) - ln (x) = 2

lo g_{9} (7 - 2 x) = 2

ln (9) + ln (x + 3) = 3

What is the answer to log_{10}(x)(32)=-5 ?
The answer to log_{10}(x)(32)=-5 is x= 1/(10^{5/32)}
Solve for x: log_{10}(x)(32)=-5
The solution is x= 1/(10^{5/32)}