What is the answer to log_{5}(x)-log_{25}(x)+log_{sqrt(5)}(x)=-5 ?

The answer to log_{5}(x)-log_{25}(x)+log_{sqrt(5)}(x)=-5 is x= 1/25

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log_{5}(x)-log_{25}(x)+log_{sqrt(5)}(x)=-5

lo g_{5} (x) - lo g_{25} (x) + lo g_{5} (x) = - 5

x = \frac{1}{25}

Decimal

x = 0.04

Solution steps

lo g_{5} (x) - lo g_{25} (x) + lo g_{5} (x) = - 5

Apply log rules

x = \frac{1}{25}

Verify Solutions:

x = \frac{1}{25}

True

The solution is

x = \frac{1}{25}

lo g_{2 x} (3 x^{2} + 6 x - 5) = 2

lo g_{64} (x) = - \frac{4}{3}

6 ln (5 x + 2) + 6 = - 6

- ln (x) = 0

lo g_{\frac{1}{5}} (0.5 x + 3) = - 1

What is the answer to log_{5}(x)-log_{25}(x)+log_{sqrt(5)}(x)=-5 ?
The answer to log_{5}(x)-log_{25}(x)+log_{sqrt(5)}(x)=-5 is x= 1/25
Solve for x: log_{5}(x)-log_{25}(x)+log_{sqrt(5)}(x)=-5
The solution is x= 1/25