What is the answer to solvefor d,p=42.6+26log_{10}(d)+20 ?

The answer to solvefor d,p=42.6+26log_{10}(d)+20 is d=10^{(p-62.6)/(26)}

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solvefor d,p=42.6+26log_{10}(d)+20

solve for

d, p = 42.6 + 26 lo g_{10} (d) + 20

d = 1 0^{\frac{p - 62.6}{26}}

Solution steps

p = 42.6 + 26 lo g_{10} (d) + 20

Switch sides

42.6 + 26 lo g_{10} (d) + 20 = p

Group like terms

26 lo g_{10} (d) + 42.6 + 20 = p

Add the numbers:

42.6 + 20 = 62.6

26 lo g_{10} (d) + 62.6 = p

Move

62.6

to the right side

26 lo g_{10} (d) = p - 62.6

Divide both sides by

26

lo g_{10} (d) = \frac{p - 62.6}{26}

Apply log rules

d = 1 0^{\frac{p - 62.6}{26}}

Verify Solutions:

d = 1 0^{\frac{p - 62.6}{26}}

True

The solution is

d = 1 0^{\frac{p - 62.6}{26}}

lo g_{8} (x) = (\frac{4}{3})

\frac{- 2 ln ( x ) + 1}{x ^{3}} = 0

y, lo g_{y} (x) = 2

ln (x) + ln (x + 1) = 7

lo g_{6} (- 3 + x) = 1

What is the answer to solvefor d,p=42.6+26log_{10}(d)+20 ?
The answer to solvefor d,p=42.6+26log_{10}(d)+20 is d=10^{(p-62.6)/(26)}