What is the answer to log_{4}((x+3)/4)=-1 ?

The answer to log_{4}((x+3)/4)=-1 is x=-2

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log_{4}((x+3)/4)=-1

lo g_{4} (\frac{x + 3}{4}) = - 1

x = - 2

Solution steps

lo g_{4} (\frac{x + 3}{4}) = - 1

Apply log rules

\frac{x + 3}{4} = 4^{- 1}

Multiply both sides by

4

\frac{x + 3}{4} \cdot 4 = 4^{- 1} \cdot 4

Simplify

4^{- 1} \cdot 4 : 1

x + 3 = 1

Solve

x + 3 = 1 : x = - 2

x = - 2

Verify Solutions:

x = - 2

True

The solution is

x = - 2

lo g_{10} (x) = \frac{1}{5}

lo g_{4} (2 x^{2} + 10 x + 16) = 2

lo g_{10} (2 x) = 2

lo g_{3 x + 2} (2 x + 1) = 0

2 lo g_{5} (2 x - 3) = 8

What is the answer to log_{4}((x+3)/4)=-1 ?
The answer to log_{4}((x+3)/4)=-1 is x=-2
Solve for x: log_{4}((x+3)/4)=-1
The solution is x=-2