What is the answer to 0=log_{3}(2x-3)-4 ?

The answer to 0=log_{3}(2x-3)-4 is x=42

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0=log_{3}(2x-3)-4

0 = lo g_{3} (2 x - 3) - 4

x = 42

Solution steps

0 = lo g_{3} (2 x - 3) - 4

Switch sides

lo g_{3} (2 x - 3) - 4 = 0

Move

4

to the right side

lo g_{3} (2 x - 3) = 4

Apply log rules

2 x - 3 = 81

Solve

2 x - 3 = 81 : x = 42

x = 42

Verify Solutions:

x = 42

True

The solution is

x = 42

ln (x) = \frac{1}{8}

x, lo g_{2} (x) = 5

2 lo g_{10} (x) = 10

x ln (x) = x

lo g_{10} (x) = 0.8531

What is the answer to 0=log_{3}(2x-3)-4 ?
The answer to 0=log_{3}(2x-3)-4 is x=42
Solve for x: 0=log_{3}(2x-3)-4
The solution is x=42