What is the answer to log_{10}((8x+1)^2)=2 ?

The answer to log_{10}((8x+1)^2)=2 is x= 9/8 ,x=-11/8

Solve for x: log_{10}((8x+1)^2)=2

The solution is x= 9/8 ,x=-11/8

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lo g_{10} ((8 x + 1)^{2}) = 2

x = \frac{9}{8}, x = - \frac{11}{8}

Decimal

x = 1.125, x = - 1.375

Solution steps

lo g_{10} ((8 x + 1)^{2}) = 2

Apply log rules

(8 x + 1)^{2} = 100

Solve

(8 x + 1)^{2} = 100 : x = \frac{9}{8}, x = - \frac{11}{8}

x = \frac{9}{8}, x = - \frac{11}{8}

ln (x - 2) = - 1

ln^{2} (x) - 4 = 0

lo g_{2} (x + 2) = - 3

lo g_{10} (x) - lo g_{10} (6) = 2 lo g_{10} (4)

ln (x) + ln (x - 4) = ln (3 x)

What is the answer to log_{10}((8x+1)^2)=2 ?
The answer to log_{10}((8x+1)^2)=2 is x= 9/8 ,x=-11/8
Solve for x: log_{10}((8x+1)^2)=2
The solution is x= 9/8 ,x=-11/8