What is the answer to log_{8}(3x^2+9x-20)=2 ?

The answer to log_{8}(3x^2+9x-20)=2 is x=4,x=-7

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log_{8}(3x^2+9x-20)=2

lo g_{8} (3 x^{2} + 9 x - 20) = 2

x = 4, x = - 7

Solution steps

lo g_{8} (3 x^{2} + 9 x - 20) = 2

Apply log rules

3 x^{2} + 9 x - 20 = 64

Solve

3 x^{2} + 9 x - 20 = 64 : x = 4, x = - 7

x = 4, x = - 7

lo g_{2} (6 \cdot 2^{2 x + 1} - 6) = x

lo g_{10} (3 x + 1) - lo g_{10} (2 x - 3) = 10

lo g_{0.5} (x) = 4

- 20 = lo g_{10} (x)

3 ln (x) = 12

What is the answer to log_{8}(3x^2+9x-20)=2 ?
The answer to log_{8}(3x^2+9x-20)=2 is x=4,x=-7
Solve for x: log_{8}(3x^2+9x-20)=2
The solution is x=4,x=-7