What is the answer to log_{x+1}(x^2+3)=2 ?

The answer to log_{x+1}(x^2+3)=2 is x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{x+1}(x^2+3)=2

lo g_{x + 1} (x^{2} + 3) = 2

x = 1

Solution steps

lo g_{x + 1} (x^{2} + 3) = 2

Apply log rules

\frac{ln ( x ^{2} + 3 )}{ln ( x + 1 )} = 2

Multiply both sides by

ln (x + 1)

\frac{ln ( x ^{2} + 3 )}{ln ( x + 1 )} ln (x + 1) = 2 ln (x + 1)

Simplify

ln (x^{2} + 3) = 2 ln (x + 1)

Apply log rules

x^{2} + 3 = (x + 1)^{2}

Solve

x^{2} + 3 = (x + 1)^{2} : x = 1

x = 1

Verify Solutions:

x = 1

True

The solution is

x = 1

6 lo g_{x} (27) = 18

lo g_{10} (x) + lo g_{10} (x + 4) = 5

lo g_{10} (x) + lo g_{10} (x + 4) = 1

lo g_{x} (2) = 0.3562

lo g_{10} (x^{2} - 6 x + 9) = 0

What is the answer to log_{x+1}(x^2+3)=2 ?
The answer to log_{x+1}(x^2+3)=2 is x=1
Solve for x: log_{x+1}(x^2+3)=2
The solution is x=1