What is the answer to log_{10}((x+1)^2)=2 ?

The answer to log_{10}((x+1)^2)=2 is x=9,x=-11

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log_{10}((x+1)^2)=2

lo g_{10} ((x + 1)^{2}) = 2

x = 9, x = - 11

Solution steps

lo g_{10} ((x + 1)^{2}) = 2

Apply log rules

(x + 1)^{2} = 100

Solve

(x + 1)^{2} = 100 : x = 9, x = - 11

x = 9, x = - 11

lo g_{x} (x^{5} + x - 1) = 5

ln (x (x + 3)^{2}) = 3

lo g_{3} (a) = - 5

4 ln (x) - 4 = 0

ln (\frac{x}{2}) + 1 = 0

What is the answer to log_{10}((x+1)^2)=2 ?
The answer to log_{10}((x+1)^2)=2 is x=9,x=-11
Solve for x: log_{10}((x+1)^2)=2
The solution is x=9,x=-11