What is the answer to 9^{log_{9}(3x-5)}=x+7 ?

The answer to 9^{log_{9}(3x-5)}=x+7 is x=6

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9^{log_{9}(3x-5)}=x+7

9^{l o g_{9} (3 x - 5)} = x + 7

x = 6

Solution steps

9^{l o g_{9} (3 x - 5)} = x + 7

Apply log rules

3 x - 5 = x + 7

Solve

3 x - 5 = x + 7 : x = 6

x = 6

Verify Solutions:

x = 6

True

The solution is

x = 6

4 ln (8 x - 2) + 2 = 10

x^{l o g_{5} (x)} = 25 x

8 = - lo g_{10} (x)

ln (x) - ln (x - 1) = 2

lo g_{2} (3 x - 4) = lo g_{2} (5)

What is the answer to 9^{log_{9}(3x-5)}=x+7 ?
The answer to 9^{log_{9}(3x-5)}=x+7 is x=6
Solve for x: 9^{log_{9}(3x-5)}=x+7
The solution is x=6