What is the answer to -3.01=20log_{10}(K) ?

The answer to -3.01=20log_{10}(K) is K= 1/(10^{0.1505)}

Solve for K: -3.01=20log_{10}(K)

The solution is K= 1/(10^{0.1505)}

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- 3.01 = 20 lo g_{10} (K)

K = \frac{1}{1 0 ^{0.1505}}

Decimal

K = 0.70713 \dots

Solution steps

- 3.01 = 20 lo g_{10} (K)

Switch sides

20 lo g_{10} (K) = - 3.01

Divide both sides by

20

lo g_{10} (K) = - 0.1505

Apply log rules

K = \frac{1}{1 0 ^{0.1505}}

Verify Solutions:

K = \frac{1}{1 0 ^{0.1505}}

True

The solution is

K = \frac{1}{1 0 ^{0.1505}}

3 lo g_{9} (5 x - 5) = 5

lo g_{3} (x^{2} + 2 x + 2) = - 1

2 = - lo g_{10} (x)

y, - ln (y) = x

20 lo g_{10} (x) = 6

What is the answer to -3.01=20log_{10}(K) ?
The answer to -3.01=20log_{10}(K) is K= 1/(10^{0.1505)}
Solve for K: -3.01=20log_{10}(K)
The solution is K= 1/(10^{0.1505)}