What is the answer to ln((x+2)^2)=12 ?

The answer to ln((x+2)^2)=12 is x=e^6-2,x=-e^6-2

Solve for x: ln((x+2)^2)=12

The solution is x=e^6-2,x=-e^6-2

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ln ((x + 2)^{2}) = 12

x = e^{6} - 2, x = - e^{6} - 2

Decimal

x = 401.42879 \dots, x = - 405.42879 \dots

Solution steps

ln ((x + 2)^{2}) = 12

Apply log rules

(x + 2)^{2} = e^{12}

Solve

(x + 2)^{2} = e^{12} : x = e^{6} - 2, x = - e^{6} - 2

x = e^{6} - 2, x = - e^{6} - 2

lo g_{4} (x^{2} + x + 3) = 1

ln (2 x + 4) = 3

6 lo g_{10} (x - 7) = 13

lo g_{10} (2 x - 3) = 0

2 lo g_{10} (3 x - 2) = 4

What is the answer to ln((x+2)^2)=12 ?
The answer to ln((x+2)^2)=12 is x=e^6-2,x=-e^6-2
Solve for x: ln((x+2)^2)=12
The solution is x=e^6-2,x=-e^6-2