What is the answer to (-3ln(x)+1)/(x^4)=0 ?

The answer to (-3ln(x)+1)/(x^4)=0 is x=\sqrt[3]{e}

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(-3ln(x)+1)/(x^4)=0

\frac{- 3 ln ( x ) + 1}{x ^{4}} = 0

x = 3 e

Decimal

x = 1.39561 \dots

Solution steps

\frac{- 3 ln ( x ) + 1}{x ^{4}} = 0

Multiply both sides by

x^{4}

- 3 ln (x) + 1 = 0

Move

1

to the right side

- 3 ln (x) = - 1

Divide both sides by

- 3

ln (x) = \frac{1}{3}

Apply log rules

x = 3 e

Verify Solutions:

x = 3 e

True

The solution is

x = 3 e

lo g_{3} (12 - 5 x) = 2

ln (3 x + 2) = ln (5 x - 6)

- lo g_{10} (k) = 3.14

a, lo g_{10} (a) = 3

ln (x + 1) = 2 - ln (x)

What is the answer to (-3ln(x)+1)/(x^4)=0 ?
The answer to (-3ln(x)+1)/(x^4)=0 is x=\sqrt[3]{e}
Solve for x: (-3ln(x)+1)/(x^4)=0
The solution is x=\sqrt[3]{e}