What is the answer to log_{7}(x^2-6x)=1 ?

The answer to log_{7}(x^2-6x)=1 is x=7,x=-1

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log_{7}(x^2-6x)=1

lo g_{7} (x^{2} - 6 x) = 1

x = 7, x = - 1

Solution steps

lo g_{7} (x^{2} - 6 x) = 1

Apply log rules

x^{2} - 6 x = 7

Solve

x^{2} - 6 x = 7 : x = 7, x = - 1

x = 7, x = - 1

lo g_{5} (x + 1) = 3

lo g_{10} (3 x + 5) + lo g_{10} (x) = 1

lo g_{x} (7) = \frac{1}{3}

- 3 = lo g_{x} (\frac{1}{8})

x, y = lo g_{g} (x)

What is the answer to log_{7}(x^2-6x)=1 ?
The answer to log_{7}(x^2-6x)=1 is x=7,x=-1
Solve for x: log_{7}(x^2-6x)=1
The solution is x=7,x=-1