What is the answer to log_{10}(w-12)=4.9 ?

The answer to log_{10}(w-12)=4.9 is w=10^{4.9}+12

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log_{10}(w-12)=4.9

lo g_{10} (w - 12) = 4.9

w = 1 0^{4.9} + 12

Decimal

w = 79444.82347 \dots

Solution steps

lo g_{10} (w - 12) = 4.9

Apply log rules

w - 12 = 1 0^{4.9}

Solve

w - 12 = 1 0^{4.9} : w = 1 0^{4.9} + 12

w = 1 0^{4.9} + 12

lo g_{6} (x + 4) + lo g_{6} (x - 2) = lo g_{6} (4 x)

lo g_{10} (x) = - 2.2

(lo g_{5} (x))^{2} + 5 lo g_{5} (x) + 6 = 0

0.001 = \frac{ln ( x )}{x}

20 x^{3} ln (x) + 9 x^{3} = 0

What is the answer to log_{10}(w-12)=4.9 ?
The answer to log_{10}(w-12)=4.9 is w=10^{4.9}+12
Solve for w: log_{10}(w-12)=4.9
The solution is w=10^{4.9}+12