What is the answer to log_{2}(x^2)+log_{2}(1/x)=1 ?

The answer to log_{2}(x^2)+log_{2}(1/x)=1 is x=2

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log_{2}(x^2)+log_{2}(1/x)=1

lo g_{2} (x^{2}) + lo g_{2} (\frac{1}{x}) = 1

x = 2

Solution steps

lo g_{2} (x^{2}) + lo g_{2} (\frac{1}{x}) = 1

Apply log rules

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

y, ln (y) = k t + ln (r)

ln (x - 7) + ln (x + 8) = 1

40 = lo g_{10} (x)

ln (y) = e

2 = ln (x)

What is the answer to log_{2}(x^2)+log_{2}(1/x)=1 ?
The answer to log_{2}(x^2)+log_{2}(1/x)=1 is x=2
Solve for x: log_{2}(x^2)+log_{2}(1/x)=1
The solution is x=2