What is the answer to solvefor y,log_{x-y}(8)=-3 ?

The answer to solvefor y,log_{x-y}(8)=-3 is y=-(1-2x)/2

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solvefor y,log_{x-y}(8)=-3

solve for

y, lo g_{x - y} (8) = - 3

y = - \frac{1 - 2 x}{2}

Solution steps

lo g_{x - y} (8) = - 3

Apply log rules

\frac{1}{lo g _{8} ( x - y )} = - 3

Multiply both sides by

lo g_{8} (x - y)

\frac{1}{lo g _{8} ( x - y )} lo g_{8} (x - y) = - 3 lo g_{8} (x - y)

Simplify

1 = - 3 lo g_{8} (x - y)

Switch sides

- 3 lo g_{8} (x - y) = 1

Divide both sides by

- 3

lo g_{8} (x - y) = - \frac{1}{3}

Apply log rules

x - y = \frac{1}{2}

Solve

x - y = \frac{1}{2} : y = - \frac{1 - 2 x}{2}

y = - \frac{1 - 2 x}{2}

Verify Solutions:

y = - \frac{1 - 2 x}{2}

True

The solution is

y = - \frac{1 - 2 x}{2}

\frac{x}{2} = x ln (x^{2})

\frac{ln ( x ^{3} )}{4} = (ln (x))^{3}

3 - lo g_{2} (5 x - 2) = 0

lo g_{11} (x) = 2

ln (x (x - 2)) = 0

What is the answer to solvefor y,log_{x-y}(8)=-3 ?
The answer to solvefor y,log_{x-y}(8)=-3 is y=-(1-2x)/2