What is the answer to log_{5}(x^2-2x-10)=2 ?

The answer to log_{5}(x^2-2x-10)=2 is x=7,x=-5

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log_{5}(x^2-2x-10)=2

lo g_{5} (x^{2} - 2 x - 10) = 2

x = 7, x = - 5

Solution steps

lo g_{5} (x^{2} - 2 x - 10) = 2

Apply log rules

x^{2} - 2 x - 10 = 25

Solve

x^{2} - 2 x - 10 = 25 : x = 7, x = - 5

x = 7, x = - 5

a, - 4 = 2 b + 2 lo g_{a} (2)

lo g_{3} (x - 3) = 4

lo g_{a} (9) = (2)

lo g_{\frac{1}{2}} (x - 3) = - 3

2 ln (x) - 3 = 0

What is the answer to log_{5}(x^2-2x-10)=2 ?
The answer to log_{5}(x^2-2x-10)=2 is x=7,x=-5
Solve for x: log_{5}(x^2-2x-10)=2
The solution is x=7,x=-5